Rate Equation

First Law of Thermodynamics:

Derivation:

ΔEδt=Δ(KE)δt+Δ(PE)δt+ΔUδt=δQδt−δWδt

Rate Equation:

dEdt=d(KE)dt+d(PE)dt+dUdt

Heat transfer rate (Q˙):

Q˙=limδt→0δQδt

Rate of work(i.e. power) (W˙):

W˙=limδt→0δWδt

Second Law of Thermodynamics:

Continuous Process:

Steady State:

dSdt=0⇒0≥∑Q˙T